Saturday, October 10, 2009

IIT-JEE-Chemistry-Final Revision Set No.73

1. Number of lone pair (s) in XeF4 is/are
(a) 0
(b) 1
(c) 2
(d) 3

2. 0.004 M Na2SO4 is isotonic with 0.01 M glucose. Degree of dissociation of
Na2SO4 is

(a) 75%
(b) 50%
(c) 25%
(d) 85%

3. 100 mL of a liquid contained in an insulated container at a pressure of 1 bar.
The pressure is steeply increased to 100 bar. The volume of the liquid is
decreased by 1 mL at this constant pressure. Find the DH and DU.

4. Draw the shape of XeF4 according to VSEPR theory. Show the lone
pair of electrons on the central atom.

5. Draw the shape of OSF4 according to VSEPR theory. Show the lone
pair of electrons on the central atom.

Source
1,2 screening 2004
3,4,5 main 2004 JEE

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